Statistics Independent Events

MooMooMath and Science
43 followers
2 Video Views·Jan 9, 2024
Independent events are events that do not affect the probability of another event.
In statistics the and means to multiply.
You multiply when you see "and"because it is the intersection of two events.
If event "A" occurring does not impact event " B" then it is an independent event.
In this video I work three independent event example problems and the probability that an event may occur.
Resources Independent Events
Probability - Independent Events Example
https://www.youtube.com/watch?v=7QlZjoLmg3I
Calculating Probability - " And " statements, independent
https://www.youtube.com/watch?v=xgoQeRyvw5I
[Music]
welcome back to moomoomath today we're
going to look at
independent and dependent events so i'm
going through our note taking guide okay
independent and dependent events these
are and problems and in math and
problems one f event occurs and a second
event occurs
we are
not going to add we're actually going to
multiply so and we always think of in
math as adding but we don't and the way
to remember that in probability is this
do not add d do not add okay so it's
kind of an acronym to help us remember
we don't add we end up multiplying so
you're going to multiply the two
probabilities together when you see and
which is the intersection
of two events okay
so
event a occurs occurring does not affect
the probability of event b that's an
independent event so if you flip a coin
and then you draw a card they don't
affect each other or if you flip a coin
and then pick it up again and flip it
again the first event doesn't affect the
second event so those are independent
events events that don't affect each
other okay so let's look at some
examples
of independent events a coin is tossed
and a six-sided dice is rolled so as you
can see
the the coin toss and the rolling of the
dice they don't affect each other
find the probability of landing on a
head on the coin
and rolling a three on the die okay so
what's the probability of landing on a
head well we have heads and tails so we
have two choices so getting a head is
one out of two
and we're going to multiply that times
because it's an and problem
so do not add multiply rolling a three
on a dice well three on a die is one
chance out of six because we have six
sides on a die
so we're going to multiply that together
and that just gives us 1 12. so that's
the probability of that event occurring
okay let's look at another one
a card is chosen at random from a deck
of 52 cards
if it then is replaced
and a second card is chosen what's the
probability of choosing a jack
and an eight okay well the probability
of choosing a jack we have four jacks in
the deck and we have 52 cards
and then it's an and problem so we're
going to multiply and then at 8 well we
have 4 8
out of 52
and we replace the cards so we still
have 52 cards to choose from
so i'm just going to reduce these before
i multiply them this is going to be 1 13
times 1 13
which is 1 out of 169 and that would be
my probability okay
so let's look at the next one a jar
contains three red
five green two blue and six yellow
marbles so marbles chosen at random from
the jar after replacing it so you
replace it a second marble's chosen
what's the probability of choosing a
green and a yellow okay so replacement
when you do replacement that is
independent
independent means if the first event
doesn't affect the second one so you
have the same number of marvels to
choose from so what's the probability of
choosing the green well green we have 5
out of let's see
that's 8 9 10 out of 16
times and means do not add multiply
yellow yellow is 6
6 out of 16.
now i'm going to go ahead and reduce
5 16 doesn't reduce but
this reduces to 3 8. now i can multiply
and i can get 15 out of
what's 16 times 8
16 times 8
is 128
so there is my probability okay 15 out
of
128
a school survey found that 9 out of 10
students like pizza
if three are of these
are chosen at random with replacement
what's the probability that all three
students like pizza
okay our first
one is our first chance is a nine out of
ten we have nine chances out of ten but
then we do it a second time and we put
the same kids back in the dar and choose
again and third one same probability so
we have three events occurring so we
have to multiply that together that
gives us nine times nine times nine
which is i should know that
729
out of 1000
and that would be our probability 729
times out of a thousand tries we would
get all three people like
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