Euclid's Pythagorean Theorem

History TV Epic
4 followers
5 Video Views·Sep 29, 2024
[EN] Geometry of the 3D Pythagoras' Theorem | A film by Luis Teia
Remember in like grade 8 when you learned about the Pythagorean Theorem?
a squared plus b squared equals c squared for any right angle triangle.
Simple enough, but if your class was like my class
you didn't learn why this theorem is true. Well today
Via De Scientia proves the Pythagorean Theorem.
The ancient philosopher Euclid lived in Alexandria around 300 years before the
Common Era.
Euclid wrote a series of books called Elements in which he proves a variety of
geometrical theorems.
Euclid's work was very different from the math we know today because in Euclid's
time
algebra hadn't been invented yet. No one ever wrote an equation,
graphed a function, or used a variable. All Euclid had was a straight edge and a
compass.
So all he could do was draw straight lines and perfect circles.
Using those two techniques Euclid was able to design methods for constructing
various objects
and to prove a number of theorems that are still extremely relevant today.
Euclid's version of the Pythagorean Theorem is devoid of equations
because algebra hadn't been invented yet. Rather
it states in right angled triangles the square on the side subtending the right
angle
is equal to the sum of the squares on the side containing the right angle.
In plain English Euclid says that if we construct a square on each side of a
right triangle
then the two smaller squares always add up to the area of the bigger square.
In this case the area of the red square plus the area of the blue square equals
the area of the pink square.
Now let's prove it. First we will give the points on the triangle names.
The points are labeled A, B, and C such that the angle
BAC is a right angle. So the theorem claims that the square of AB
plus the square of AC equals the square of BC.
We can construct the pink square BE which is just the square of the
hypotenuse.
Euclid had a particular method to do this using only a straight edge and
compass
but for the sake of keeping our diagram simple we will just assume this is
possible.
We can use the same method to construct the other two squares
AF and AK here shown in red and blue
respectively. Now we have our setup and we can start the proof.
We now draw a line from A that is perpendicular to the hypotenuse
perpendicular to BC. This line must intersect the segment DE at some point
so let's give that point a name and call it L. We will now use a straight line
segment to connect points A and D
to form line segment AD. We can also connect C and F the same way.
Notice that CBD and ABF
are both right angles so if we add angle ABC to each of them
they would still be equal. We thus know that angle DBA
is equal to the angle CBF. Because the pink and red squares are well
squares we know that BD is equal to BC and
that AB is equal to BF. If two triangles have the same two sides at
the same angle
they must be equal triangles so we know the triangle ABD
is equal to triangle BCF. Now consider this
the area of a parallelogram is base times height and the area of a triangle
is base times height over 2.
That means that if a parallelogram and a triangle have the same base and height
the triangle has half the area of the parallelogram no matter what the angles
are.
That means that the area of the triangle ABD
is exactly half the area of the parallelogram BL
which shares the base BD. That also means that the area of the triangle BCF
is half the area of the parallelogram BG which shares the base BF.
So that means because the two triangles are equal
that the area of the rectangle BL is the same as the area of the square
BG. We can then use the same method by drawing these lines to show that
this triangle is equal to this triangle. Similarly this allows us to show that
the areas of these two parallelograms
are equal. So we've shown that the red square has the same area as the red
rectangle and the blue square has the same area as the blue rectangle.
But we also know that the red rectangle and the blue rectangle
add up to the pink square. Thus we have shown that the areas of the red square
and the blue square
add up to the area of the pink square. A squared plus B squared equals C squared
which is exactly what we were trying to show.
Thanks for watching! I hope you enjoyed learning why the Pythagorean theorem is
as right as the triangles it describes.
As you can see equations are not necessary to do good math.
Geometry is more than equal to the task. Do you have any feedback on this video
or suggestions for future videos?
Then leave them in the comment section below. Also don't forget to press the
like button and the subscribe button!
