Welcome to “An Intro to the Distributive Property” with Mr. J! Need help with simplifying expressions using the distributive property? You're in the right place!
Whether you're just starting out, or need a quick refresher, this is the video for you if you're looking for help with the distributive property. Mr. J will go through examples of the distributive property and explain how to simplify expressions using the distributive property.
✅ Chapters and Timestamps 00:00 - Intro 1:04 - Number 1 2:52 - Number 2 4:00 - Number 3 5:52 - Number 4
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Hopefully this video is what you're looking for when it comes to simplifying expressions using the distributive property.
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welcome to math with Mr Jay
[Music]
in this video I'm going to go through an
introduction to simplifying algebraic
expressions using the distributive
property now the distributive property
can help us remove parentheses within
algebraic expressions this helps us
simplify expressions when we do not have
like terms within parentheses that we
can combine now remember when we have
something next to parentheses that means
multiplication so we can use the
distributive property to distribute
whatever is on the outside of the
parentheses to the terms inside the
parentheses the distributive property
works when we have addition or
subtraction inside of the parentheses so
at the top of the screen there is a
general overview of the distributive
property where a is being distributed to
the terms inside of the parentheses the
distributive property and that overview
will make a lot more sense as we go
through our examples let's just jump
into number one where we have two and
then in parentheses five plus three and
we're going to do this two different
ways by using the order of operations so
doing what's in the parentheses first
and then also using the distributive
property now for number one we don't
have any variables involved we are
actually able to add what's in the
parentheses first and then go from there
we don't have to use the distributive
property but the point of number one is
to show us that we get the same thing
either way this is going to show us that
the distributive property doesn't change
the value of an expression we are able
to use this strategy so again we get the
same thing either way let's start by
using the order of operations and doing
what's in the parentheses first we have
five plus three
which is eight
bring down the two and now we have two
times eight
which is 16.
now let's Use the distributive property
and see if we still get 16. so we need
to take that 2 on the outside of the
parentheses
and distribute it to the 5 and to the 3.
so we have
two
times five plus
two
times three two times five
gives us 10 plus 2 times 3 gives us 6.
10 plus 6
is 16. so we get 16 that way as well so
we can see that the distributive
property doesn't change the value of an
expression and we are able to use it
let's move on to number two where we
will apply this to an algebraic
expression in order to simplify the
expression we are going to remove the
parentheses for number two we have 8 and
then in parentheses 2m plus six now we
can't combine those terms in the
parentheses so what we can do we can use
the distributive property to remove
those parentheses and simplify this
expression so let's distribute the 8 to
the 2m
and to the 6. this gives us 8
times 2m
Plus
eight
times six eight times two m
is 16 M plus eight times six
is Forty-Eight now 16 M and 48 are
unlike terms so we don't have any terms
that we can combine so we are
done here 16m plus 48 is our simplified
expression let's move on to number three
where we have 7 and then in parentheses
a minus 9. let's distribute that 7 to
the A
and to the nine that gives us 7
times a minus bring the subtraction sign
down 7
times 9.
7 times a is just seven a
minus seven times nine
is 63. so we end up with 7A minus 63. we
don't have any like terms that we can
combine
so we are simplified and done again 7A
minus 63. now I do want to mention
another way to think through this and
this is another way to Think Through
whenever subtraction or negatives are
involved so let me rewrite the
expression
and then distribute
the 7.
so we have 7 times a which is 7A and
then we can think of that subtraction
sign and the 9 as a negative 9. so
including the sign in front with the
nine so we think of that as a negative
nine so let's distribute that 7 to the
negative nine seven times negative nine
is negative
63. so negative
63 and we get 7A minus 63 that way as
well and again that's just a different
way to Think Through It you get the same
thing either way but you can include the
sign in front of the term and think of
that as a negative 9. so something to
keep in mind let's move on to number
four where we have 10 and then in
parentheses negative 5x minus 4y let's
distribute the 10 to the negative 5X
and to the 4y so 10 times negative 5x
minus 10 times 4
y 10 times negative 5x gives us negative
50 x minus 10 times 4y gives us 40 y so
we end up with negative 50x minus 40y we
don't have any like terms that we can
combine
so we are done again negative 50x minus
40y now let's take a look at a different
way to think through this
so I will rewrite the expression off to
the side so let's
distribute the 10 to the negative 5x and
then we will think of that as negative
4y so include the sign in front of that
term 10 times negative 5x is negative
50 x and then 10 times negative 4y is
negative
40y so we get the same thing that way as
well negative 50x minus 40y so there you
have it there's an introduction to the
distributive property check the
description for a link to Part 2 where I
go through four more examples I hope
that helped
thanks so much for watching
until next time peace
you know