I always want to hear your feedback so drop a comment down below ✅
okay so if we have a look at this
question here we have another nine Mark
super about question again something
very typical to come up we have a l
accelerates uniformly from 5 to 20 m/s
in 30 seconds find how far it travels
whilst accelerating so realistically
again we probably don't need a diagram
for this one but I always draw diagrams
just as a good habit so let's quickly
discuss all the different ways that I'm
going to help you in your GCC or a level
maths careers first of all I wanted to
talk to you about the YouTube members
this is a really costeffective way of
getting tutoring so I'm going to do
weekly live streams for GCSE and a-level
maths and that all comes for £18 a month
and you get at minimum an hour of
tutoring per week in these live streams
at the moment they're quite small so you
basically get tuition for about £450 an
hour which is really really cheap the
second thing is the patreon for those of
you doing a level maths I have already
completed as stats on my patreon is a
full class with worksheets mark schemes
videos I answer all the questions we're
going to do exam papers and everything
that needs doing we're halfway through
mechanics as of yet and lastly there's
tuition I still have places in my group
classes for a level maths and GCSE Maths
for GCS it's £30 an hour and for a level
is40 per hour so if you want to let me
know if you're interested just email me
or join the Discord where I'm very very
active all the time anyways back to the
video I'm going to represent the Lor as
just a little box and it goes from 5 m/s
and it goes
to 20
m/s and we want the actual distance that
it travels in that time and that time is
30 seconds so again we can write out our
suat equation so we have S is equal to
don't know that's what we want U is
equal to 5 b is equal to 20 a is equal
to don't know and T is equal to 30 now
the cool thing about suat is that as
long as you have three variables you can
work out the other two guaranteed so we
can get straight to s s from here now of
course because we have three variables
we could also work out a and then work
out s if we want to so it really is up
to use if you get stuck on how to get
from these three variables straight to S
think about well how do I work at a
instead then and then use a different
equation that's the beauty of it as long
as you have three variables you're
golden now of course the equation that
has s u v and T in it is actually s
equals U + v/ 2 T so if we sub that n we
have 5
+ 20/ 2 * 30 and we can get that out now
so let's pull out our calculator so
that's going to be 25 over 2 which is
12.5 * 30 probably didn't need a
calculator for that but whatever
375 m is how far it travels now of
course that's not too bad so what you'll
find with a lot of suat questions is the
first part is quite quick so we're going
to get three marks just for that really
really really fast but the real meat of
the question is the six or seven marker
that you have afterwards or you have
multiple other parts as well but find in
seconds corrector 2dp the length of time
it takes for the lobby to cover the
first half of this distance and you know
what I find that this happens quite a
lot where students get a bit stuck on
this now first of all let's just write
out what we know well s is going to be
half of 375 so if I just quickly divide
that by two on the
calculator we get 187.5 m 1 8 7.5 M and
actually I didn't need put the M but
whatever U is still five cuz it's the
first half of the distance if it was the
last half of the distance we would know
V is 20 right uh V we don't
know a we also don't know and T is going
to be what it says first half of the um
well we want the times we don't have
that so as you can see we're kind of
screwed because we have only two known
variables now there are a few different
things you can do in order to work out
exactly what's going on and here's what
I would do if you remember when we do
suat we have constant acceleration so I
could work out acceleration from part A
and it would be the same as the
acceleration in Part B because remember
the acceleration has to be constant
throughout the whole thing so from a if
we use the um part A equations we can
say that a is equal to B- U / T so 20 -
5
over 30 which is going to be 15 over 30
which is a half so
0.5 that's my new
value for a and now we have everything
we need s equal UT plus half
a^2 and that is where a lot of students
lost marks because they
didn't and this is a really cool thing
with a level mats if you really want to
get that a star if you really do want to
get there and also impress people in
your interviews for universities you
need to understand the maths it's not
good enough to be able to regurgitate
information like you can in GCSE you
have to understand why you're doing it
and again that's how you get to the A's
and a Stars okay you need to understand
this question is not difficult if you
understand that sua is constant
acceleration which means the
acceleration from part A will give you
part B now there are a few lucky people
who happened to work out a in part A and
then then work out s but most people
jumped straight to S and they didn't
know a jumped to the second part and got
stuck I only know two variables it's
impossible it's not impossible it can't
be impossible so enough of me kind
of smack talking you uh that would be 5T
plus a half a t^2 well a half a is going
to be
0.25 T ^2 uh shove everything over to
the right hand side will probably be the
easiest and write it out as a quadratic
equation so like like
so and now all we need to do is use our
calculator that's six Mar
Mar that's why I love mechanics you get
a lot of marks for realistically not
that much work but you have to use your
brain and that's the bit that a lot of
people get struggle
on two polom degrees two so 0.25 in
front of the squared ter there's a five
in front of the linear term and there is
a -
187.5 for the constant term at the end
and we get two values of course we do um
I probably haven't given myself enough
space
though
34 and then we're also going to
get -10 - 5 <
tk34 now which one are we going to go
for we are going to go for the positive
value because keep in mind time cannot
be negative the reason why we get
Negative answers here is because it's a
quadratic model okay so because we're
assuming that our values are going to
follow a u shape or an N Shape there's
going to be two values for every single
um point on there even if it doesn't
make any sense because we tend to be
looking at only the first half or the
last half of the curve so we're going to
take positive value which is it has to
be this one so that is a bit lazy of me
though so let's go back to the normal
mode Let's actually work out what it is
does it say to any so it says to two
decimal places so let's quickly um sub
that in and see what we get so
-10 plus < TK
34 5un 34 even that is correct and it
should be -1 come on here we are
shocking thank you calculator 19 it says
just two decimal places so T is equal to
19.15 seconds to two decimal places
again I'd always recommend writing the
exact value as well just so the examiner
can see but that here is six
marks not that bad in my
opinion