# mathematics #matholympiad | a^2 + b=73, b^2+a =73, solve for a and b

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# mathematics #matholympiad | a^2 + b=73, b^2+a =73, solve for a and b
Math Olympiad Problems
ABCD+ABCD+ABCD+ABCD= DCBA: Solution:
Mysterious numbers Kaprekar’s Constants 6174 and 495
AI Generated·May contain errors
Video Summary
AI GeneratedThis video provides a step-by-step algebraic solution to find the values of $a$ and $b$ given the equations $a^2 + b = 73$ and $b^2 + a = 73$, under the condition that $a \\neq b$. Through subtraction, factoring, and solving a quadratic equation, the final solutions are determined to be $(9, -8)$ and $(-8, 9)$.
Hello friends in this video, we are going to discuss an algebraic equation solve for a B if a square plus B equal to 73
B square plus a equal to 73
With the condition a not equal to B now to solve this equation. We are going to
Subtract 2 from 1 and we have a
square plus B minus B square plus a
Equal to 73 minus 73
By opening the brackets. We have a square plus B
This minus is multiplied with the brackets and we have minus B square minus a
equal to 73 minus 7 3 equal to 0
now
Gathering the similar term a square with minus B square and B with minus a
Taking the factors of a square minus B square a minus B a plus B
B minus a can be written in the form of minus times a minus B equal to 0
Now we can observe that a minus B is a common factor between two terms
so we can take out from this two terms and we have a minus B a
plus B and
minus 1 we have property
Multiplication of two number is 0 that one of the number must be 0
therefore we have a
minus B equal to 0 or a plus B minus 1 equal to
If we simplify then we have a equal to B and a plus B equal to 1
but we have given that a
Not equal to B. That means a equal to B is not possible
hence, we have a
plus B equal to 1 now from this equation a plus B equal to 1 we can write down B equal to 1 minus a
substitute that value in equation 1 then we have a
Square B equal to 1 minus a equal to 73 now simplify
Then we have a square minus a plus 1 minus 73
equal to 0
1 minus 73 equal to minus 72
therefore we have a square minus a minus 72 equal to 0 it is a quadratic equation and
We want to find the roots of this equation
For that we have to find the factors of 72
whose subtraction is
Minus 1 and the factors are 9
Into 8 equal to 72 so 9 and 8 are the factor so we can rewrite the equation a square
minus 9 a plus 8 a minus 72 equal to 0 a
Is a common factor in first two terms and 8 is a common factor in the last two terms
Therefore we have a minus 9 and a plus 8 equal to 0 with the similar property
Multiplication of two number is 0 then one of the number must be 0
therefore we have a minus 9 equal to 0 or a plus 8 equal to
If a minus 9 equal to 0 then a equal to 9 and a plus 8 equal to 0 then a equal to minus 8
suppose a equal to 9 then
B equal to
1 minus a equal to 1 minus 9 equal to minus 8 therefore B equal to minus 8 if
A equal to 9 then B equal to minus 8
Suppose a equal to minus 8 and B equal to 1 minus a equal to 1 minus
Minus 8 minus minus plus so we have 1 plus 8 equal to 9
Therefore be equal to that means a equal to minus 8 then B equal to
Therefore we had two possible solution of the equation a
square plus B equal to 73 and B square plus a equal to 73
Are a equal to 9 and B equal to minus 8 or a equal to minus 8 and B equal to
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