A math olympiad exponential math problem|solve for x.

JJ ONLINE MATHS CLASS
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This video is a full tutorial on how to solve an exponential math problem using the rules of exponents and logarithms. #matholympiad #exponents #logarithm
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Video Summary
AI GeneratedThis video provides a step-by-step mathematical tutorial on solving an exponential equation to find the value of $x$ when $27^x = 162$. The instructor demonstrates how to use logarithms to isolate the variable, simplify the resulting expression using logarithmic laws, and verify the final answer by substituting it back into the original equation.
Back to this place to get 162, okay. Welcome to my channel. I'm going to solve this and then
I'll also substitute it back to this to show that what we did is correct; I think that is the
the most interesting aspect of this video, so don't miss that aspect, okay? Now we are asked to solve
for x, yes, everyone knows that this is the only way, or the only approach to this, is if we introduce
Take the logarithm of both sides of the equation. Okay, so we are going to introduce the logarithm to both sides of the equation.
equation, so we are going to have log one six two. All right, now when you have log a to the power of
b this becomes b multiplied by log a, all right? Now we are going to bring this down, so we are
going to have x multiplied by log 27 is equal to log 100 and what 62 all right now when you
Look at this; you can see, let's divide both sides of this equation by log 27 divided by log 27.
because that is the only way I can get the value of my x now; this we divide, and we have
x is equal to log 162 divided by log 27. Now we are going to simplify this further. Yes, we can.
just leave this the way it is, let's simplify further, so to do that we have log 162 in terms of
log 27 can be written as what x is equal to log 27 multiplied by 6, yes, okay, 27 multiplied by 6
divided by log 27. Now I want us to recall our logarithmic law that states that
log of a multiplied by b is equal to log a plus log b, okay, so since we have this here
We are going to add them, so we'll have that x is equal to log 27 plus log 6.
divided by log 27, all right, so we can write that x is equal to log 27 divided by log 27
plus log 6 divided by log 27. Now when this divides this, we are going to have one, right?
That means we can write this as x equals 1 plus log 6 divided by log 27.
Now x is equal to one plus, we can further express log 6 as log 3 times 2, right?
So we write this as log 3 multiplied by 2, okay? This is multiplication: 3 multiplied by 2, now.
divided by log 27 is the same thing as 3 to the power of 3; now we solve that x is equal to one plus
now we can write log 3 plus log 2, okay, just like I explained initially, divided by, then this will
Come down to give us 3 log 3. Now you can see that we have another two parts of this particular
So we have that x is equal to 1 plus log 3 divided by 3 log 3, okay? Now plus log 2.
divided by 3 log 3, all right? If this is the first time you're coming across this channel
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If you are actually enjoying this particular video, thank you so much. Now from here, we can see that
x equals one plus, now what do we have here? We divide this, so we have one over three.
one over three plus this becomes log two, or you can call this one over three multiplied by
what log 2 divided by log 3 all right yeah okay now what do we have that x is equal to one over
we give us what if we take our lcm to be three I'm going to use uh what is it called the
butterfly method: one times three gives us three, plus one times one gives us one, so we are going
to end up with four over three, okay, so I will write four over three here, so we have four over
three plus one over three log; now when you have log a divided by log b, this is the same thing as log a
base b, so we can write this as log base 3 of 2. Now this becomes our equation or the value of x.
Now we are going to substitute this back into the particular question to prove that what we obtained
Yes, okay, now it's time to prove that what we have is correct. Okay, so all of this is our x.
now let's substitute it into this equation to see if we are going to get
162 Okay, so we'll write that 27 to the power of 4 over 3 plus 1 over 3 log
the cube root of 2, okay, that everything equals 162, okay. Now recall that a to the power of m
plus n is equal to a to the power of m multiplied by a to the power of n, so we are going to use that
the same formula or that same law here, so we are going to have 27 to the power of 4 over 3 plus
Sorry, multiplied by 27 to the power of 1 over 3 log 2 base 3 is equal to 162. Okay, now recall that
27 is the same as 3 to the power of 3, so we can write this as 3 to the power of 3 raised to
the power of 4 over 3 multiplied by 3 to the power of 3 raised to the power of 1 over 3 log
2 to the power of 3 is equal to 162, okay. All right, now 3: we divide 3; here we have 3 to the power of 4.
multiplied by now this 3 also divide this 3 and we have 3 to the power of log 2 base 3
All right, is equal to 162 now. 3 to the power of 4 is 81, so we'll write 81 multiplied by
Now, when you have a to the power of log b base a, this is the same thing as what? This is equal to b.
to be so we can now write the whole of this as what the whole of this is equal to 2 is equal to 162
Now it's one times two, we get 162, and 162 equals 162. Thank you so much for watching.
Have a lovely day
