To determine the current sensitivity of a moving coil galvanometer #12thphysics @a2zpractical991

Main iitek First of all, I'm dodging 19 thousand You can save it for 10.5 thousand, however much you want Hello, friends! Welcome to my channel. Today I grammed again with a new experiment. To determine the current sensitivity of a moving coil This is your Experiment No. 7, and it is a very important experiment. In front of you, you just need to pay attention to one thing. You have to draw the circuit diagram very neatly in the board exam. It seems you can only start the experiment properly once you have the circuit diagram. You must remember it exactly as I will explain it in the circuit diagram. Come on, let's try an experiment—I was about to start Fast Start for you, but Front, please do me a favor and do one thing for me. Subscribe to this channel and give me a lot of support So that I can make a lot of videos for you Alright, let me start this experiment. Do not skip even a single bit of this video. This is a very good physics experiment and a very exciting experiment. Okay, this is my very best for you, meaning a message, just consider it as such. Because if you don't do this, there will be too many problems. So, friends, one more thing I'd like to tell you is please support my channel The more people you share it with, the better. So, let me show you how to do an experiment. You don't need to go anywhere, Fronts—I've already uploaded all the physics and chemistry practicals into it. I have uploaded the practical file. The first line that comes after zero, the first line that comes after zero If it's 5 times 5, then it goes like 5, 10, 15, 20, and so on, up to 50. And I have this up to 250. How much is this? 250 Are you still here, Parishot? This Rehearsed Code Which one is the second one, and which one will it connect to? Will connect to Micrometer To which one will it be connected from the positive terminal? From the positive terminal of the micrometer What you're seeing here is the connection. These two sites are not to be identified. Vaccines? Vaccines, Parallel, and all this We don't need to know, so we won't directly use the Micrometer Connect to the galvanometer So, you see, this will also be done at your college. Well then, let me tell you something interesting. So I'll directly tell you the video connection. The negative part of this is, Who will connect? What about its negative part? Will it connect? From the positive part of the galvanometer? Its positive part Here, it will connect. And after that, the one who The current is not flowing for the sake of the parrot's own sake. If this is acceptable to you So you, one by one, you, one by one, no, not from here Leave it as it is; then you will be able to come out of it. And if you ever need to go to the circuit So, the professors and others in your college Show him physics first. Then come back to the circuit; you can also remove and keep it there. What does this do to the current supply? You are looking at You must be looking at the battery. So keep it aside and move forward. Lying down, lying down No, no, don't lie down Professor comes here. So, first of all, it's removing the battery app. So first, I'll check their circuit. And What should I do with it? It has a battery, and the switch is here. If they're switching to the Ganga vaccine, you're watching closely, just in case anything goes wrong—I'm getting a sense that something might be off. How much is one digit in this, how much is phi? As in 150, then after 150 The first digit will be the one for phi, won't it? Fine, ten is fine like this I just arrived at Galvino Meter Filal here Changed it because look You must have seen that in your college Too many, if you don't apply them Somewhere in micrometers, somewhere in galvino meters If you stay, you'll be the one to check out later. First, I will give you an experiment. What am I supposed to do here, first reading Luga, okay, I've turned the lights off. Alright, then the first reading I'm giving you is I'll start, I'm here with the resistils I'm coming to pick up my friend; my friend is here waiting for you. You must be seeing this number; it's ten thousand. 5,000, and this one is 15,000 This is 17,000 And it will be done. 19,000 What am I doing, I'm leaving from here, you We can do it at 10, we can also do it at 5000 I have given the Elegan Thienos to Sabraiya. So, do you mean for 19,000? How much is the value coming here? Coming in, 105, it's a hit And how much is being received here, why are both here? It's a side effect, also occurs between 0 and 30 I'll take you out for 17 So this became 10,000, this 15 These are 16, 17, meaning what needs to be done with this for the 19th? Close the 19th one. Now for 17,000 For 17,000 How much value am I getting here for 17,000? Five, ten, fifteen? Five, ten, fifteen We'll do it for 10,000 for the next last one Since we need to extract the readings from our four charts, I'll close this. So Philal, for 10,000, then for 10,000 How much is being received here, let's see how much is being received. 195, how much am I getting? 195 So this has come to my reading, and there's still a lot of age to go. Calculating this is correct; this is a very easy calculation. So, let me tell you how I perform calculations and how I create graphs. A lot of effort must have gone into making this video. All the practicals for 11th and 12th are available here—go check them out, you'll love them very much. Alright, then let me show you the graph and how to calculate it. And I had shown you the EMF of the cell. Which was how much we had, two words pay. You must have noticed that I have taken four resistances here. 19,000, 17,000, 15,000, and 10,000 So, the value I was getting for my IG I mean the value of current that was coming So in amperes, that is 105 A. For the first one, and for the second one, 1 1 five is coming. 130 for the third, and 190 for the fourth. And how much deflection was being served? there, the deflection in the galvanometer So he was serving 6 for the first time. For the second, 7; for the third, 8 12 for the 4th What do you need to do here now? that you do not need to convert this into empty amperes So, from mu to empty ampere After converting, remove these mu You don't need to do anything with this 10 raised to minus 6. It has to be multiplied. 105 × 10⁻⁶ 115 × 10⁻⁶ 130 × 10⁻⁶ 195 × 10⁻⁶ s upon d theta by ig Sorry theta by ig Dhaise Threta is the deflection in the galvanometer. upon I_G which is current in ampere You have to divide it. Here it shows divided for you How will you divide? So You have to divide it by theta over ig SIX and IG's value How much is 105? Then you'll get it. 0.0571 Into 10 bistu, it will go up there So it will become 6, okay? Like that, you know It is to be done for everyone: 7 divided by 115 7 divided by 115 equals approximately 0.06087. And this is also in the 10 Bistu 6. 7 divided by 115 So this will go 0.0608 What will 6 into 10 bis too become? 6 What comes after that? 8 divided by 130 8 divided by 130 equals approximately 0.0615. You will get 0.0615 What comes after Intu 10 Bistu 6? 12 divided by 195 So how much will you get? 0.0165 In to 10 Bistu You'll get 10 biscuits, now you need to take out 6 from me What do you mean by bypassing everyone and doing 4 to deviate? If I have to do it, I'll handle all the things, all the values You'll get it, that's all. 0.06022 In to 10 Bistu 6 Now I am seeing here 10 biscuits, which were 6 you had I'll convert this to 2 digits, okay? You would know if this were in Bishtu 6, 10 So if I turn this to 2 digits here, then 10 minus 4 will be 6, what should I do with this? 6.022 I'll write it in 10 words in Bistu 4 Okay, because it's after 1 point The decimal is quite perfect, okay? You have a connection with this fire. First, the Theta by IGI matchup What is the theta bat? What is your emperor two of this—this again? I'll give you the grab. Alright, then let me quickly plot the graph for you right here. First, I plot an XY axis scatter graph An x-axis agenda Now I will take you to the scale. I'll basically scale you on the x-axis and y axis I'll take one centimeter here. And on the y-axis, I will take one centimeter is equal to one division Then I'll take you to 20 40 60 80 120 140 160 180 200 What will this become? 220 And on the y-axis, I need to take theta. that is the deflection in the galvanometer and on the x-axis, me I have to take the current that is I G So in amperes What should I do now? One centimeter is equal to one division. I have written it myself. One centimeter is equal to one division. 1, 2, 3, 4, 5, 6 7, 8, 9 10, 11 12, 13 14, 15 Now, what do you need to see first? You need to take the scale. One centimeter is equal to 20 times 10 to the power of minus 6. 20 into 10 raise to -6 You are here at the front, the value of I G What do you need to keep here? 105 into 10 raised to minus 6 And what is your theta's value? What is 6? It will come at 110 And it will be done. It will become 100. And how much will I have to pay for 195? 12 Now I'm passing it completely from the origin. Here I'll pass it right from the origin to here. So I've just passed this over here. The graph has now been prepared and is ready for us. Any two points can be taken I'm taking this point. You can take any two points. How the value is given here This will become ours. It will happen. 195 × 10⁻⁶ And the other one along with it—how much is that? 12 And how much is this, it's basically ours 1, sorry, 1, 1 5 × 10⁻⁶ And what is on the y-axis? It is 7. Alright So this will be yours, x1 This will become x2. y2 This will become your x1. y1 will become x2 y2 Now you have to sing the formula for slope. y2 - y1 is equal to x2 - x1 So, what is your y2? 12 What is minus y1? 7 x2, how much is yours, x2 yours is 195 What is minus x1 of 135? Minus 6, sorry, this is 115 How much is this? 115 × 10⁻⁶ Now you can easily subtract it yourself. That will come to you, and this will come to you. 80 × 10⁻⁶ Now divide 4 by 80. Then you will get it. 0.050 × 10⁻⁶ This is minus 6, so what will happen if we go up, 6 What will happen if you go up there? 6 You can write it in 4B format if you wish. How will you write it? You'll have to carry 2 digits over. The two digits will be taken away and kept here. So you will get this, approximately 5.0 × 10⁻⁴ You need to show now how much value you got from the graph So, I have shown you here by calculation that from the graph I obtained 5.0 × 10⁻⁴. So I got here from the graph 5.0 × 10⁻⁴ So this value remains the same What is this value? It remains the same, right? You can see this graph here; you can take a screenshot of it. And these are my readings. You can view my readings here, and you can also take a screenshot of these readings right here, fronts. So, friends, one thing, and I'd like to say please support my channel So, fronts, you must have seen the experiment, you must have liked it very much Alright, if you need such videos, or if you need physics-related experiments, So, subscribe to this channel and keep it handy—I'll help you a lot in your exams. You should check him out and take less from the help you're receiving. And also give a like to your friends, thank you, and don't forget to subscribe, add, and watch this video, thank you