Balancing Redox Reactions by Oxidation Number Method | Class 11 Chemistry @a2zpractical991

Hello, children, how are you all? Today I will teach you Redox Reaction is a very important topic that is Balancing of Redox Reaction Actually, let me tell you The balancing of redox reactions It has been categorized into two categories. The part we are going to read in this video It is basically the Oxidation Number Method. I mean, using the Oxidation Number Method, you can do your You can balance all redox reactions. And the second one, I'll teach you in the next video I will stay with the Half-cell Method, okay? Otherwise, we'll see later if the Ion Exchange Method is used. First, we will look at our Redox, which is the Chapter is a very important concept. This is the balancing of a redox reaction and we will balance the redox reaction By which method does the child Yes, oxidation number method Which method is the oxidation number method? Now let's move on to the children who are using the oxidation number method. Will you balance any reaction? So for him, there are certain rules. Write down those rules in your copy, cut to cut. Because when I teach you how to balance I'll ask based on these rules, and you'll have to respond, okay? Okay, write together, everyone, write together What needs to be done first will be whatever reaction you give me He must write it. And if that unbalanced reaction The number of atoms on the left-hand side does not match the number on the right-hand side. Then you will balance it. except hydrogen and oxygen You don't need to balance hydrogen and oxygen. The other elements that will remain If they remain unbalanced, you will balance them. Third point states: calculate the oxidation number Now, the oxidation number for everyone to calculate What does the fourth point say? Whatever oxidation number comes up You will have to perform cross multiplication with it. Inside the equations, I will tell you How will you perform multiplication? and if you get any oxidation number If he arrives at any simplest ratio Then you will calculate its ratio. Alright, man, I'll tell you everything, but first, understand the rule. You won't be able to do it if you don't understand the rule; look here, for example, the item here is 2, 6 is here, and there's 4, so how would you find its simplest ratio? 2, 3, 6, 2, 2, 4, its simplest ratio here, now You can perform cross multiplication here, okay, like this If something remains, you'll also do cross multiplication, if It's clear now—if there's no oxygen, there won't be any life either. You also need to add H2O over there, oxygen. Everyone understood, okay, the product and reactant sides Check where oxygen is low, and add H2O there. What does the next point say where you added H2O? Add H2O exactly on the opposite side of it. If you have added the product side H2O What will you add to H2O? Absolutely the opposite side yes, reactant side The last point says to check whether your reaction balance is correct or not. I will ask you questions; then you will understand very well. Rules are essential, brother. Without rules, you won't be able to do anything. Come on, come here today using the oxidation number method Here, the oxidation number method is discussed. You must show it to me balanced from here onwards. This equation is given here So what does the first step say? write unbalanced reaction So I write here an unbalanced reaction What is our unbalanced reaction? Tell me. Yes MnO₄⁻ plus Fe2 arrow Mn plus 2 plus Fe2 I wrote down the unbalanced reaction. Do we need to balance this? Here is Mn, one is here Here is an Fe, here is an Fe, here is an Fe, here is an Fe, four times Yes, there is an O here, not a zero, but you need to take the first step. If you look at it, or alternatively, look at the second step, then You have to balance the LHS and RHS, but Other than hydrogen and oxygen, how much O remains Look, first let's find out the oxidation number of this. I need to write a reaction now, regarding Mn for me I don't know, so what should I put? x plus four times What is the oxygen level, minus two over total charge? So x is equal to four two go eight is equal two minus one, so x equals seven, okay? So here, the What is the oxidation number of Mn, and how much did the child go? It's for the fruit add, let's pick one, look at one, pick one, look at one plus 2 and for Fe we do x is equal to plus 3, meaning here everyone The oxidation number has just been introduced; I will write it right below this: x is So everyone has arrived here now, regarding this oxidation number time. What turns out is paying attention, listening carefully, third point, third I need to inform you about that here Listen carefully, children, what's increasing? and decrease in oxidation number, write it correctly, okay, so I I'm putting a heading here, I'm going to remove it from here, here, here am increasing from where to where is the decrease in oxidation number What is decreasing—everything is for you to see. So let's see, first look at what your MnO4 minus was What happened to your Mn plus 2? Is it correct? What happened here? So, the child has reached you. plus 7 from Reached plus 2 Alright, so what exactly happened here? Here is yours Decrease in Oxidation Number Decrease in Oxidation Number, how many of decreased from 7 to 2 He went away, it decreased, didn't it? So it became 5, 5 here So, a problem occurred here with 5. Alright, how many problems did you have with oxidation numbers? The second reaction, what is it? The second one was our Fe plus 2 child. And in which one did he go? He went to Fe Plus 3. So, how much was here—it was in the form of plus 2 Where has it reached now in the plus 3 form? What happened here? Was there an increment? What was the increment? What is the oxidation number of chromium? Incremented by plus one plus one The increment here is five. What happened to the regiment here at the forest? The engagement there What will be the simplest ratio of five if? I write five and one like this so that it is divisible by it Isn't this our last simplest ratio? Next is yours. It says that whoever has come to you Everyone knows how to do cross multiplication. Perform cross multiplication in this equation. And here comes one, isn't it? Multiplication has to be performed in this equation. Let me also check by doing cross multiplication here. The next step is our cross multiplication. Come on If you multiply it by 1, you'll get the same result. Now, shall I just do the step, cross multiplication? Step 4, Step 4, what is it, cross multiplication How do you perform cross multiplication? Let's do it together. What is it? If you multiply MnO4⁻, you'll get the same result, right? Okay, fine. If you multiply it, you'll get the same product. What is side? It will be mn plus 2, okay, that's the same one that will come. If you multiply by pi, will it become 5 times bigger? Add 2 to Fe, and multiply it by this, and it will become 5 times Fe. Next step, step number 5 What does this say? Add H2O Where will we add H2O? Wherever ours is. Oxygen atom will appear less on this side, brother, on the product side, it's like this. Oxygen atoms keep coming, but we're not going to add anything here What is the reactant side and product side of H₂O? Not only brother, but we'll also place the ad on the H2O product side here. Is oxygen visible anywhere? Not visible, or is it low? What are we going to add there? H2O addition to H2O has been done. Let's go. What does the next step say? Addition of H plus ion Where at You added H2O exactly on the opposite side of it. If you add H Plus I, I'll add you too, I don't know You will add here H plus ions Okay, this getting what Mn plus Two plus plus file A three plus ab Now what you need to do is make these reactions fully balanced. However you do it, balancing here—how much oxygen is there? Next step, I will write down Step Number Six Balancing Which equation should I balance? I'll take the redox one. How do I balance the reaction? Pay attention, oxygen here How much is four times two? If this is four times two, then the child, if I If I do it four times, my oxygen will be four here. It will happen, it will happen that I'll write it down below How many times am I going to do this here? It's already four times. But the child has increased four worlds eight times hydrogen here It's hydrogen, so what should I do? Nothing at all, just stay here. Eight times hydrogen, I can write it here, you can write eight times hydrogen Write down this equation below and this is your final. The equation will be, and according to this oxidation method, I have What has been done with this entire redox reaction? Balance it. Got it, everyone will understand, okay, absolutely Follow these steps, yes, start I will check whether your reaction balance is correct or not. No, if something isn't in balance, like look here, this If Two F had stayed, I would have been here at this F twice. I pay it, if not, you won't even need to balance it No, it's not here. All evaluated main points to everyone. Got it, right, oxidation number without balance Don't take anything out, don't do anything, then the entire question is yours, wrong It will be okay, so this was your oxidation method, I've What was the reaction, balanced now another video The second method will come up, where we will perform ion exchange What will we do with the reaction using the method or the half-cell method? We'll balance it, okay? See you in the next video. Thank you.