HYDROCARBON || Class 11th Chemistry Maharashtra Board Chapter 15 lec-6

If you have carefully read this chapter, then the organic reactions of Class 12 will come to you completely smoothly. If you have carefully read this chapter, then the organic reactions of the twelfth grade will come to you effortlessly. Tome-ri-jis, what are Tome-ri-jis? Let me tell you. And let me tell you one thing: the acetylene you have with your triple bond is mixed with oxygen to form oxy-acetylene, which is used for welding materials. Hello, kids! How are you all doing? You must have definitely considered many practical aspects in your life. Children, I'm telling you that I've already started your Eleven Chemistry Chapter Number 15, Hydrocarbons, with the Hapne Star. And five parts of Ali Di have been completed. So today I'm going to start 6 parts. And you all know that in this hydrocarbon, there are multiple reactions occurring. And what about the reaction? Alkane, alkene, alkyne. All these reactions are available to you today in 12. Therefore, whenever I teach this chapter, and every time I tell the children, if you have read this chapter carefully So for you, those 12 organic reactions come out completely smoothly. The 6 parts I teach to children for you If you have carefully read the Math chapter Meaning, today we are going to prepare Kaiin. How many pi bonds are present between the carbon atoms in acetylene? Everyone knew this. Today we will prepare the alkyne compound And we will apply a formula or a process to it. And this process and formula are very many. Dihydrohalogenation If you have any B reactions among Hydrogen and halogen are given. So we call that one "we" Dihydrogenation If you are a virvito Vicinal Dihalides What are these Vicinal Dihalides? So, Vasinl means There is no highlight group on top of the carpan. A halo group also present above the carbonyl Such compounds are called molecules. Vicinal Dihalides Does every child know one thing? Okay sir, I know, let's go They move toward the reactions What reactions are we supposed to perform? So with Visceral Dihalides We have to perform these reactions. And the last one, we need to make alkyne Meaning of alkyne Between carbon and carbon So I'll tell you this simple thing Show it through your reactions I am taking an example here. Something like that kind of way Now look here This child I mentioned, the example Here it is taken That is the Visceral Dihalides. Why? Because a carbon and its What is adjacent to both? Yes, your Halogens group is To perform these reactions We will have to react in two steps. We will set it once. What will this KOH be like, and the child? Alcoholic KOH This alcoholic KOH As soon as you react As soon as you react Heat is necessary here As soon as you react So, tell me, what happens then? You are mistaken. What will this do? This will take the CL. And one Carbon has been lost. What will this OH do? It will take the H from the second Carbon. And I have taught you countless times A carbon was lost. In an instant, the reaction of Usai Adjacent carbon also experiences loss. So, what should be worn with the akka muni? Double bond What is the tax? Double bond Come on CS3 C CL Double bond C CH This has become our alkene. But we need acetylene. What do we need, child? I need a razor. Sodamite It will go there because that's where the reaction is possible, and look, it has an H here. It's a Cidry catch, and it has chlorine. Let me tell you one thing about all of you. Because if a carbon atom has three H atoms attached to it And there is 2H in the carbon's vicinity. And does any carbon have a 1H? So, the most dangerous one that is acidic Which can donate its protons He is near a carbon. The single H could do it like speak, that's right. I'm also telling you about these things. I'll explain—just remember this: the H here comes out And here, the H doesn't come out, okay? Well, just like you're doing with it First, when the children arrive, I'll write down one envelope will be received and one You might get ammonia, okay, the final product is yours What will be shown? This CS was C, now even this pain So, add one more bond and that will become your triple bond, okay, so do this one We can say one, two, propyne, propylene, propyne, souri, Y, meaning triple bond Hey, buddy, here's propane. What did you learn from this reaction? if you have vicinal dihalides, and OK, if you have vicinal dihalides, then you First, react with k-OH, and a halide and a hydrogen will be eliminated. Then a double bond will form, the second one, which you will do using sodamide. In the question, it is mentioned that I have taken out something from the mind, which I thought of. The triple of the dunna will be added, and the jadha will be added. Whoever becomes Gassan's successor, you will meet the bond. Everyone has gone together; it's becoming clear to me now. So we completed this reaction in two steps. In the first step, we will carry out the reaction with KOH. Write it down in theory. And in the second step, we use Sodamide OK? Okay? What is the formula of sodamide? Na-NH₂ I mean all the children From Visinol I mean, we managed to form a triple bond from the dihalide. Okay? next moving with the next reaction number Okay? Listen carefully to this reaction. from terminal alkynes What are these terminal alkynes? What is a terminal alkyne? So the children who at the end There is a chain. At the end of a chain You will see the triple bond So that is called for terminal alkyne Okay? Now this terminal alkyne Us from meaning We need to carry out a reaction with a terminal alkyne. A fish is clear. Whom are we supposed to react to? What do we need to do with the terminal alkyne? To trigger a reaction And here, the one who The product becomes yours that is higher alkyne Okay? What will happen in this formula now? So first, an example Take it. terminal alkyne Okay, I'm ready. I'll take this example here. terminal alkyne One thing first I'm letting you know. Five, your This is an alkyne. This is an alkyne. As This has become an alkyne. That's it Five, this is it acidic H is present This one, the one that is this What you are seeing H This and this Alright This cup is highly acidic H is present I mean, if someone has a reaction I am donating to this It gets scattered then It will come out from the hit. Because sp3 hybridized The carbon that exists So this one here H is quite What is it like to be easily becomes protonated is donated in reactions Now it's the same H So, get the reactions done Gives of alkyne I am giving you the Gadhata. Listen to where it's coming from Take the goods, I have you A reaction was taken Something like this CS3 triple bond CH Because And what have I told you? Terminal alkyne-containing We have Optane. Higher Alkyne And we will react to this. Lithium From amide A type of It is a strong base. Because we have An acidic H is present. With our Strong Base I'm reacting can do That is what happens plus This is what happens minus This is Acidic H It will exit from here And it will go inside its pocket. And the child What will become minus This minus this Lithium Will attract with him/her Something like this Product here with us They will begin to meet Okay Lithium will be available here Alkane Alkalanide Alkyne Lithium Alright This kind of way Okay What happens in step number 2? Listen carefully What happens in step number 2? This gives us a higher alkane. So again, we react to this Any With alkyl bromide Or else Ethyl Bromide Whatever it may be So what could possibly happen? Tell me Yes Look here Now together with this C What will this CS2 be? Will join And with this CS2 as well What will happen? Will join CS3 Lass What will happen to you, LiBr? It will go outside. Alright, so here's what I have Look, did you get the higher alkene? 1, 2, 3, 4, 5 What were you looking at here? You are here at this place From Profine Pantene has been done The one also, the second one That's it. Terminal Function of alkyne who remained Terminal carbon is present. His that It is H. The child is very cute. It is acidic. H Of any Base In presence It will come out very fast. So, right away then Use it here Alright Alkyl bromide, just as it is Use it As Reaction said, it wasn't said Make a 5-carbon compound So you are here What is 3? So I added 2 more. So, how much has it become? Look, a 5-carbon alkyne Reaction doesn't speak. Prepare a 6-carbon alkyne A 6-carbon chain is fine. Bana-ta-o Three are here Here you go, three of them. Br, take it. Li-Br will come out. So the three of them are here will be substituted And the alkyne with 6 carbons It will be found. Clear. So, all the children understand it. Reaction of Terminal Alkyne Where your Chain Length It meets by being big. It comes only after a long wait. Come on Let's write down some reaction names. Lithium amide Ethyl bromide I think you can do this reaction yourself. That you've learned so much from this reaction that you can perform Higher Alkyne Apten Why? Because of this acidic haze Terminal Carbon-Containing Acidic H Because the child becomes accustomed to this SP It contains 50% S character. And 50% P Character The one who excessively privatizes this H for acidity Okay? Next, Physical Properties of Alkynes Let us examine the physical properties of alkynes. Let's check the melting point to see whether it dissolves in it. that it does not dissolve in it So, what are we going to do with all these things? We will look into this topic. First, look at its Physical Properties Its physical properties similar to those of alkane and alkene Because this one also does not dissolve. Look, they are less dense than water Okay? If you put it in water, then This will go up above, and water will go down below. Less dense and they are insoluble in water So if it is insoluble So they are insoluble in water and quite soluble in Less Polar Organic Solvent This is our organic compound. If you dissolve this in water Organic is polar to us. You will dissolve it in there. No, bonding will not be possible. Why can one thing dissolve in another thing? Because they build bonding with him You are an organic compound. And water is an inorganic compound, child, they do not dissolve in each other. Liquin, if you've added the oil into all of this Put into non-polar organic compounds Like Ether, Benzene, Carbon, Carbon Tetrachloride So he might dissolve within it. So our alkyne is also a type of It is an organic compound, so it will also require an organic liquid. To dissolve These kids are all our Organic Liquids. After that, they look at this If you're talking about melting and boiling points So, the melting and boiling points of alkyne Increases if the molecular masses increase If you don't understand the meaning of this So I'll tell you myself You have stolen it A two-carbon alkyne taken And here is a three-carbon alkyne. Alright Its balling point will be higher. Automatically more carbon is present So, what will be its Balling Point and Melting Point? It is going to be more So, listen, I'm telling you one thing that I love you very, very much organically I'm explaining, it's way too much Why, because I want you to understand this chapter Because if you understand this chapter So you'll understand 12, and 12 will be clear to you, so somewhere, somehow, you'll definitely say thank you to me. This was a practical channel that used to be an ATU jet, intended for writing organics. I mean, when I was doing T.Y., at that time I really understood organic astrology very well. I understand very well the way he explained things—meaning, organic chemistry was extremely basic for him. He would teach the mechanism, explaining exactly what happens in an actual reaction, breaking down every single detail for people. I accepted those things and found very good meaning in them for myself. So, I would like to sincerely thank you very much, Worth College. So, Sidh, you'll surely thank me somewhere if you've finally understood this thing. You know that the terminal hydrogen of an alkyne is highly acidic and readily reacts with any base. You know that the terminal hydrogen of alkyne is very acidic, so it's easy to deprotonate. Hey, Redden, is that your ghost? What's this thing called Proton? What's going on with HBO? No, we have not forgotten you. We have kept you very, very close, with great gratitude. The past tense of "ut" has been spoken. If I talk about reactivity and Orla. Reactivity. Order order order order acidic. Alkane. Alkene. And alkyne. Whose will be more? The one with the highest S character will be Look, it has 50% S character here 50% P character is present because SP And in those with a double bond The ratio of the S character decreases. And in the case of a single bond The ratio of the S character decreases. So if I Let's talk about reactivity So the child who is your terminal position one The alkyne that will be This will be the most reactive. than this one Because What is this entire thing? Single bond What is the whole thing? Single bond If I just give a normal reaction to it A normal reaction means if the goods are with me There is such a group And here is H. So if I put Lithium in it I carry out a reaction with amide. And I'm hitting it So what possible product is there to hear here Look, this one here is negative, and this one If it's positive, then it's not negative. What will you do with this acidic H? Will you remove it? And this child who has turned out negative What will carbon do? Negative carbon? It will pull the lithium due to the s character. For this, electronegativity will increase significantly. So this Lithium to your If it attracts from the side, it will be something like this way The compound here will be made; please watch carefully So why hasn't it been cooked here? Here's the one who didn't come out? Is everyone finding out now? in the reactivity order The acidity level in it is extremely high. Which one has higher electronegativity? whose s character is higher OK? I think you'll understand the acidity of alkenes better. You will find this useful in the fairy tale. What is written here? The hydrogen-bonded C≡C bond exhibits acidic character. Lithium amide is a very strong base. and reacts with a terminal alkyne How is acidic acid? reacts and liberation of the hydrogen indicating the acidic nature of the terminal alkyne Look here What is the acidic edge here? Hydrogen evolves, reacting with it. and that will indicate an acidic nature alkyne in the terminal carbon All the children are beginning to understand. Organic is the best way However much is possible I am explaining it to you. Now it's up to you to figure out how to handle this Memorizing, how do you remember my words? Alright, kid? Next topic is addition of halogens We are studying the topic of alkyne. Whether you're reading about alkynes or not, it's okay. You can give him a reaction there until then. As long as the entire bond hasn't run out there What? Can I perform another reaction here? Look, from behind I can take br2 here. This BR2 will break this bond from the back. And what will happen up there? It will be substituted, look carefully Watch, I'll show you. This br was here Look, what will happen now? This bond will break. And the br2 you just used Then a line break will be substituted here. A br will be substituted here. That's it—the addition of halogens to alkanes What should I write here? on alkanes Because we are carrying out the reaction on alkanes My topic has always been this from the beginning. Okay? Now I'll do something about it What will its name be? There's nothing in it, is there? Just understand, you used a BR2 USB. So a bond was broken The second one also underwent br2, so the second one also experienced bond break. It was a double bond; I broke it. It won't break just by breaking the last bond. Because single bond As it is, like a coin That's how it connects, and a double bond How does Maggie break? It breaks. There is this kind of overlapping happening here. next addition of hydrogen halides to alkynes How many people know about hydrogen halides? hydrogen halides I mean, you can use this instead of that. HCl, HBr, and HI Does anyone know his reactivity? Which hydrogen halides react? I'll discuss it now; first, let me react. As you have done here alkynes taken I took the alkynes here. And I'm reacting to it. with hydrogen halides First of all, this reaction here You have to cover that up. Markovnikov's rule What is it according to Markovnikov's rule? the negative part goes to a doubly bonded carbon carries fewer hydrogen atoms Every child knows this. plus to minus Now tell me, where will the negative charge go? The bond you're going to take It will shift here, this will happen here. Who will attract the minus? What will we get here? Now look, br, it's come here A bond broke, and If there was an s, how much did it become h? There still exists a bond. There is another bond there at the double bond. So, let's go again, I'm coming back from there I react it with HBr along with BR2. And just as you are with H(extreme)B(R) I will react. What will you feel, child? Here it was negative positive negative bond goes to a doubly bonded carbon carrying less number of hydrogen atoms this will go here this The bond will shift to minus. Did it. So, what's going to happen here? A billboard was placed here, here. Something like that was two. B.R. will be installed here shortly. And what will it become from two? It will become three. So this addition is nothing but what Mark its role And what will this become? Two dibromopropane, and what will this become? One two thine, so it's pyrene, this is pyrene. It's very difficult to understand, the meaning is unclear. If you can break one bond, then the other is alternatively the second bond. There's also a Pi bond; even that you'll break, and after reacting the same way, you'll say it. Sir, a worm bond child, I'm breaking you. Child, you won't be that. You're sigma-pointed. Speak up. Hey, man, don't you write the name? Okay, I'll write it down—One Two Two Groomoo Propene. Alright, here we go. One I was wondering what the Markonik rule states—that is, what it says about the negative part going to the preplacental bond at carbon carrying a lesser number of hydrogen atoms. Please tell me one more thing. For the addition reaction of alkyne, I have an alkyne group, and I add water to it. Water means H2O, H+, and OH. Now, to carry out the Ota Syryakshn, we must exert effort; we will endure 45 percent of this heavy burden C. And temple at 15 percent older male's haddam It will come out from here, it will come out H, plus will come out, okay? Alright, so tell me, what product will come? What will be formed from CS3, C, Double Bond, Single Bond, CS2? CS2, what will happen to you? Ketone, and which ketone is it? Tell me about this? So, in Tato, you understand, where the head is located, Bond shifting, how to do bond shifting? In all, these are double bonds, meaning alcohols, these bonds are here, these bonds are here, this will become, Are all the children understanding everything? Am I over-explaining? It's not very difficult, these seasons, I remember, so you might remember too, you just need some practice. You've seen all the procedures, right? Can you tell me what kinds of things you could prepare using thiol bonds? I've already shown you how to make a ketone; before that, I demonstrated how to make an acid, ethanoic acid, and ethanol, among others. Second, You can also produce plastics using ethane, which is another point you can mention. The third point relates to this, specifically regarding artificial ripening and ripening fruits, where we use these triple-bonded compounds. And one thing I'd like to tell you: the acetylene that you have in your triple bond is actually oxidized acetylene, formed by mixing with oxygen, and it was used as a welding material, right? So in welding, what have we been doing with it all along? Your Hindi ################################################################## has ended. Now the next topic is ours. An aromatic compound refers to a type of organic compound characterized by a ring structure with delocalized electrons, typically exhibiting enhanced stability and unique chemical properties. The term "aromatic" originally described compounds with a distinct smell, but now it specifically denotes compounds that meet certain criteria, such as planarity, cyclic structure, and the presence of (4n + 2) π electrons in the ring, following Hückel's rule. These compounds include benzene and its derivatives, as well as other systems like naphthalene and anthracene. What are the reactions of an aromatic compound, and how do these reactions occur? I'll make you all feel our wrath—you have no reason to fear. Because they are also part of your Class 12 syllabus, and I've taught you organic chemistry so lovingly, dear child, from afar. Any child who sees all my notes won't be able to say, "Dude, what has this guy taught? This teacher!" I've already given you my base. I want you to make such notes and do such practice that you also become the best in organic chemistry. That's what every teacher deeply wishes—that the children they've taught study properly, understand concepts well, and score good marks. See you in the next video, where we'll be discussing aromatic compounds in detail. Beyond that, Vic's Xan Sik Kenge Than K, this is good, these are good names, and if you like this video, please like and subscribe, the next video is coming.