Experiment no 3 || Chemical kinetics || class12th chemistry practical @a2zpractical991

To study the effect of concentration on the rate of reaction between sodium thiosulphate and HCl Hello everyone, how are you all doing? You must know about this channel, A2Z Practicals. Are all the practicals available with you? You go, keep an eye on him. All of your Matlab 11th and 12th practicals are available on this channel. Today, I have come here with the practicals I have prepared. This is your Experiment No. 3 But which class? To the 12th Experiment No. 3 for Class 12 Chemistry I am present here, as requested. That is your chemical kinetics. Now we will see what is meant by chemical kinetics In chemical kinetics, we study only the rate of reaction. Which reaction does MATLAB use, and in how many steps? How fast are you running? It depends on the concentration of the reactants. If you have reactants in Matlab It is for high molarity. Then I took a high concentration (solution). The reaction will have to follow up speedily. But if you've reduced your concentration What will be the reaction? What will happen here in such a short time? Come on In this way, we define chemical kinetics. In Matlab chemical kinetics, we basically perform numerical simulations and analyses of chemical reaction systems, including solving differential equations that describe reaction rates, modeling reaction mechanisms, fitting kinetic parameters to experimental data, and visualizing concentration changes over time. Study the rate of the reaction Alright, our aim is our practicals' So what exactly are we supposed to do here? To study the effect of concentration on the rate of reaction Between sodium thiosulfate and SCL In MATLAB, we use sodium thiosulfate and SCL We determine the rate of reaction to find out k The fascinating thing about these practicals is the children. What are we going to do? The solution of sodium thiosulfate Jo is concentrated and given to you. They will keep diluting it again and again. We will keep the concentrated solution at the end. Let's see what increases the rate of reaction here. They move toward the patapat reaction. Sodium thiosulfate reacts with 2 moles of SCl₂. There is a formation of sulfur. Other bioproducts are also produced in this process. However, sulfur is present in very important amounts in this. As a precipitate, yours It falls into the conical flask. We're the ones who'll be watching all the practicals Sulphur means Sulfur is a solution with a milky color. It will be formed in your conical flask Then what will your reaction be? The child will stop soon. So, while I was doing time-based work Let's start the practicals. But child, tell me one thing that I am giving you practicals through this video. And what about its calculation The part with the graph You can go to its link and check You can go to the playlist and check it out. Playlist MATLAB That would be your description. You go and do the calculation part We can make a graph there. Alright, and also on the I buttons You will get videos for this. Alright, I'll start then Your experiment number 3 That is chemical kinetics. Those who react with disgust Who against whom Sodium thiosulfate and HCl So, kids, to carry out this experiment What do you have to do? You need to take four conical flasks Label the four conical flasks. That's the main thing I do here. Label it as A You need to put a cross mark here Place this conical flask here. You must place the entire conical flask with it. That is your B Your C will be done. That will become yours, sir. Put a cross mark What should be done with the conical flask? Accordingly, it needs to be arranged. If you already know your tables Who is left in each conical flask? Different quantities Sodium thiosulfate must be added. You have sodium thiosulfate with you. With this sodium thiosulfate solution What should I do? I will add it to a conical flask. As given in your handbook Add 20 ml in the previous one. What am I supposed to do here? 20 ml of sodium thiosulfate I will add it to the previous conical flask. For you, 20 ml of sodium thiosulphate What did you do in the previous conical flask? Added it. You want to add the other person to the chat 30 ml Oh In the 3rd wale, you need to add it 40 ml You need to add it in the 3rd wale. 40 ml Oh You need to add it in the 5th one 50 ml You've added it already. Listen carefully What is Hume's experiment? Hi Hume needs to determine everyone's rate of reaction. Which one will form sulfur faster in a conical flask? The sooner the milky color appears We must determine this ourselves. We are not determining the milky color just like that. You will see that from inside the conical flask You should be seeing a cross mark inside the conical flask. What will it look like? What do you think you see? A cross mark will appear inside the conical flask. What can you see inside the conical flask? Cross mark The jab reaction will be complete. To thee cross mark na The conical flask should disappear. You can see the cross mark here It should disappear You can see the cross mark Just as we will add the entire solution here We'll see whether the cross mark actually disappears properly. Alright Noticing What should we do? What have we done, us people? Sodium thiosulfate has been added. Our next point is that we need to add it for everyone. In the previous conical flask, you have Add 28 ml We will add 18 ml to the other one. We will dilute less We will make the third wale more concentrated and less diluted. What do you need to add in the previous beaker? 28 ml H₂O What should you add to the other beaker? 18 ml 18 ml of water What should be added in the other one? 18 ml of water We need to add the third wale 8 ml of water How much should be added for the third wale? 8 ml In the final mixture, we don't need to add water at all. Matlab, let it stay concentrated. You must keep him focused. Last wale D, we did not dilute anything. Listen carefully That's your third step. You have to add it to all of them 2 ml HCl Add 2 normal HCL. I have two normal HCLs with me. And now, what to do with 2-2 ml? Should it be added? As I had to add 2 ml of HCl into the beaker earlier I want to stop the stopwatch. Whatever reading comes to you, I will write it for you. Why So kid What should we do now? Add 2 ml of HCl as in the previous case? What should we do? We'll just start the stopwatch. Alright, let's take 2 ml of HCl. I have 2 ml of HCl here. And now it's your turn I am doing the Konical task. What do you want to do with the stopwatch? Turn it on? So, you just added 2 ml to it. What did you do to my stopwatch? I have mice. From now on, you are to observe this The stopwatch tab will keep running for you As long as it appears inside it The cross mark should not disappear. As it is, a cross mark You disappear How do you feel about seeing this? Exactly the eyes you should have It should be exactly parallel to this. How should parallel be? Exactly, if your eye is perfectly parallel to it If the cross mark disappears What should one do to attain liberation? Write down the Wahi reading So you can see now, slowly, gradually My skin started turning milky in color. You can see this conical task. Already seen If you're seeing this cross mark here If it disappears like this, it will vanish You're looking at me, aren't you? You shouldn't look. As soon as this disappears What will I do with the main stopwatch? I'll turn it into a child. It has completely disappeared. I think the entire cross mark has disappeared. I will stop the stopwatch. To you, my cross mark has completely disappeared entirely. How many did you basically disappear for? It happened. 20, 30, 40, 45 25 years old He had already disappeared in 25 seconds. It took me a little time to turn this off. Because I wanted to show you this You won't see this cross mark, I assure you. What were you supposed to do? I had to stop the stopwatch. What were you supposed to do with the stopwatch? I had to keep going. You won't be able to see this cross mark. You can see, but the cross mark won't be able to see you Okay You want to do this to everyone, don't you? Alright What should we do? Vapas se 2 ml HCl solution What are we going to do with the child? 2 ml HCl solution What should we do with it in the other one? We will transfer We will transfer to the other beaker. Now we will transfer it into the other beaker. We will turn on the stopwatch. You see, I've already transferred it into here. What did you do with the stopwatch? On cardia We'll note it down when his time comes. We must treat everyone in this way. If it becomes Matlab, add 2 ml to it. Add 2 ml when it becomes like this. So finally The boy has gradually disappeared. You've already disappeared Matlab disappeared after one minute and 15 seconds. That is One minute fifteen seconds means 75 seconds, you can say so. I'm stopping right here. I'm a bit late in stopping. 75 seconds to me Matlab one minute 15 seconds 20, you may appear to be fine Its color disappeared in just 15 seconds. The cross mark that I want to see He had disappeared.<(),) One minute is 60 seconds. Plus 15 you need to add To total 75 seconds For the previous one, this happened in 140 seconds. For the other one The milky color appeared at what time? It has been 75 seconds since it appeared. Alright, now in the third one, we will again add 2 ml We'll see when it happens. I also need to add 2 ml in the third wale. What should I do with my stopwatch, kid? Give it to me. What should I do with the stopwatch? Give it to me. What else do I have to do for this? Need to check Its rate of reaction is extremely fast. Because we are the ones who make the nectar so extremely diluted Look, this sulfur is getting really hot. I think its readings will come very soon. I think the bacha is turning milky-colored here. What is happening with that cross mark? Completely disappearing right now I don't see it yet. Okay The cross mark on ours has already disappeared. To those who like readings You can write for one minute and 5 seconds. We'll do the third one. How quickly does the last one disappear? We'll take a look wherever we go. Okay In the last one, I added 2 ml of acid. What else can I do? I'll start it again. Okay Let's also take a look at the last one. Look, in the last one, you didn't even add a single drop of water It is a concentrated solution. If this is a concentrated solution Its rate of reaction was extremely high. Is it possible to produce this product? It's extremely fast. This product is by Hume. It will be met within at least 40 to 45 seconds. Because it has already been running for 25 seconds The product has already started arriving./AFP Like milky color solution formation It has already started. So now you've understood how to do it Is the experiment very easy or not? Alright You know, I think you're disappearing completely from the dark side. It has already happened. It has already been settled. My 45 or 46 will arrive today's readings. Alright So, the kid, did you see the practical? It was very easy. The previous one was reading 2 minutes 20 seconds. Lakbak How many seconds are there in 1 minute? 60 seconds In 2 minutes, 120 And add those 20 seconds there for you. I think it will take 140 today. The other guy was getting 75. The third one is showing 65. It was coming from around 45. That's what it means What are you looking at here? You are seeing here that The more concentrated your solution became Where I hadn't diluted it with water You were so fast that I couldn't keep up with your readings. Matlab quickly in time I am coming today What did I explain here and how did I explain it? Where will you get the calculations and graphs from? What did he say to me? You are now checking by clicking the I button Here is its description. Puri aapke calculation aur graphs banaye hue Please go there and open the description box. Click on the videos available there Be sure to watch those videos For your calculation purposes and for your graph purposes How did you kids like this experiment? Please comment box me, your comments should be there That's the point regarding his calculations and graphs. What did you say to me? These are videos. Your calculations and graphs will be available there for you. Thank you for watching this video And please subscribe to A2J Practicals Thank you